JavaScript by Patrik

Use a shouldSkip Local Variable

If you can't use every() or slice(), you can check a shouldSkip flag at the start of your forEach() callback. If you set shouldSkip to true, the forEach() callback returns immediately.

// Prints "1, 2, 3"
let shouldSkip = false;
[1, 2, 3, 4, 5].forEach(v => {
  if (shouldSkip) {
    return;
  }
  if (v > 3) {
    shouldSkip = true;
    return;
  }

  console.log(v);
});

This approach is clunky and inelegant, but it works with minimum mental overhead. You can use this approach if the previous approaches seem too clever.