JSON Deserialization in C#

To deserialize JSON into a dynamic object in C# using System.Json, follow these steps:

1. Parse the JSON string using JsonValue.Parse() to obtain a JsonValue object.
2. Convert the JsonValue object to a dynamic object using the JsonValue.ToDynamic() extension method.

Here's an example code snippet:

using System.Json;

string jsonString = "{\"name\":\"John\",\"age\":30}";
JsonValue jsonValue = JsonValue.Parse(jsonString);
dynamic dynamicObj = jsonValue.ToDynamic();

Console.WriteLine($"Name: {dynamicObj.name}, Age: {dynamicObj.age}");

For more advanced JSON deserialization scenarios in C#, using libraries like Json.NET (Newtonsoft.Json) is recommended. 

Some helpful links

• Deserialize JSON object into dynamic object using JSON.NET: This Stack Overflow thread provides insights into using JSON.NET to deserialize JSON into dynamic objects, offering code examples and explanations.
• C# Deserialize JSON into Dynamic Object: This tutorial from Code Maze explores deserializing JSON into dynamic objects in C# using Newtonsoft.Json.
• Deserializing dynamic JSON: Here, you can find discussions and solutions for deserializing dynamic JSON objects using different libraries and techniques.
• Deserialize JSON string into dynamic object using System.Text.Json: This Stack Overflow post delves into deserializing JSON strings into dynamic objects using System.Text.Json.
• Serialize C# anonymous type to a JSON string: Explore serialization of C# anonymous types to JSON strings, which can be relevant for dynamic object handling.
• Deserialize JSON into list of anonymous type: Learn about deserializing JSON into a list of anonymous types, which can be part of handling dynamic JSON data structures.